(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=?简便算法

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(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=?简便算法

(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=?简便算法
(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=?
简便算法

(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=?简便算法
观察单项：
1/8=(1/2-1/4)/2
1/24=(1/4-1/6)/2
1/48=(1/6-1/8)/2
1/80=(1/8-1/10)/2
1/120=(1/10-1/12)/2
1/168=(1/12-1/14)/2
1/224=(1/14-1/16)/2
提出来1/2；括号内很容易求和；
即：
（1/2-1/16）*64/2=16-2=14

(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64
=(1/2-1/4+1/4-1/6+....+1/14-1/16)/2*64
=(1/2-1/16)*32
=5/16*32
=10

1/8+1/24+1/48+1/80 1/8+1/24+1/48+1/80简便计算 (1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64= (1/8+1/24+1/48+1/80+1/120+1/168+1/224)乘64 (1/8+1/24+1/48+1/80+1/120+1/168)简便计算 （1/8+1/24+1/48+1/80+1/120+1/168）乘以56 （8/1+24/1+48/1+80/1+120//1+168/1）*42 1/8+1/24+1/48+1/80+1/120+1/168 （1/8+1/24+1/48+1/80+1/120+1/168）*56 42x(8/1+24/1+48/1+80/1+120/1+168/1)=?求求 42X（1/8+1/24+1/48+1/80+1/120+1/168）求解 8分之1+24分之1+48分之1+80分之1+120分之1=? 8/1+24/1+48/1+80/1+120/1要过程 1/8+1/24+1/48+1/80+.+1/360 = 1/8+1/24+1/48+1/80……+1/2400=? 1/2+1/8+1/24+1/48+1/80要简便哦 1/2 +1/8+1/24+1/48+1/80怎么做 1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99怎么求