作业帮有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 08:44:07
![有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1](/uploads/image/z/12662435-11-5.jpg?t=%E6%9C%89%E4%B8%80%E4%B8%AA%E5%88%9D%E4%BA%8C%E7%9A%84%E8%A7%A3%E6%96%B9%E7%A8%8B%E6%80%8E%E4%B9%88%E7%AE%97%3A%5B%28a%2B1%29%5C%28a-1%29%2B1%5C%28a-1%29%26%23178%3B%5D%C3%97a%5Ca-1)
有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1
有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1
有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1
[(a+1)\(a-1)+1\(a-1)²]×a\a-1
=【(a+1)(a-1)+1】\(a-1)²xa\a-1
=a²\(a-1)²xa\a-1
=a3/(a-1)3
a的3次方/（a-1）的3次方
记得给满意啊
=[(a+1)(a-1)-(a-1)]/(a-1)(a-1)*a/a-1 =a3/(a-1)3 题目有点怪,没错吧?
a3/(a-1)3