若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为

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若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为

若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为
若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为

若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为
cos(pai/4+α)=sin(π/4-α)=5/13,cos2α=sin2(π/4-α)=2sin(π/4-α)cos(π/4-α)=2*5/13*12/13=120/169 ,故待求式=(120/169)/(5/13)=24/13