一个matlab求符号函数的拐点的问题syms x a b c d e yy=(a-b)/(1+exp((x-c)/d))+b/(1+exp(-x/e));ddydx=diff(diff(y,'x'));x=solve(ddydx,'x')Error using ==> solveError,(in allvalues/rootseq) cannot evaluate with symbolic coefficients这是怎么

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一个matlab求符号函数的拐点的问题syms x a b c d e yy=(a-b)/(1+exp((x-c)/d))+b/(1+exp(-x/e));ddydx=diff(diff(y,'x'));x=solve(ddydx,'x')Error using ==> solveError,(in allvalues/rootseq) cannot evaluate with symbolic coefficients这是怎么

一个matlab求符号函数的拐点的问题syms x a b c d e yy=(a-b)/(1+exp((x-c)/d))+b/(1+exp(-x/e));ddydx=diff(diff(y,'x'));x=solve(ddydx,'x')Error using ==> solveError,(in allvalues/rootseq) cannot evaluate with symbolic coefficients这是怎么
一个matlab求符号函数的拐点的问题
syms x a b c d e y
y=(a-b)/(1+exp((x-c)/d))+b/(1+exp(-x/e));
ddydx=diff(diff(y,'x'));x=solve(ddydx,'x')
Error using ==> solve
Error,(in allvalues/rootseq) cannot evaluate with symbolic coefficients
这是怎么个情况?

一个matlab求符号函数的拐点的问题syms x a b c d e yy=(a-b)/(1+exp((x-c)/d))+b/(1+exp(-x/e));ddydx=diff(diff(y,'x'));x=solve(ddydx,'x')Error using ==> solveError,(in allvalues/rootseq) cannot evaluate with symbolic coefficients这是怎么
你的程序没有问题的,但是最后的这个方程是没有解析解的,因为这个方程很复杂.