解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)如题,求步骤简单明了.

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解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)如题,求步骤简单明了.

解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)如题,求步骤简单明了.
解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)
如题,求步骤简单明了.

解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)如题,求步骤简单明了.
1.4(x+3)²=25(x-2)²
4(x+3)²-25(x-2)²=0
[2(X+3)+5(X-2)][2(X+3)-5(X-2)] =0
[2X+6+5X-10][2X+6-5X+10]=0
(7X-4)(-3X+16)=0
X=4/7或X=16/3;
2.(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
X=0或
X=(1-√2)/(1+√2)
=(1-√2)²/(1-2)
=-(1-√2)²
=-3+2√2
X=0或X=-3+2√2

4(x+3)2-25(x-2)2=0
[2(x+3)+5(x-2)][2(x-3)-5(x-2)]=0
所以2(x+3)+5(x
-2)=0huo2(x-3)-5(x-2)=0解出即可
x[(1+√2)x-(1-根号2)】=0
所以x=0或1+√2)x-(1-根号2)=0解出即可

1,解方程:
4(x+3)²=25(x-2)²
4(x+3)^2-25(x-2)^2=0
[2(x+3)+5(x-2)][2(x+3)-5(x-2)]=0
[7x-4][16-3x]=0
7x-4=0 x1=4/7
16-3x=0 x2=16/3 .,
2,
(1+√2)x²-(1-√2)...

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1,解方程:
4(x+3)²=25(x-2)²
4(x+3)^2-25(x-2)^2=0
[2(x+3)+5(x-2)][2(x+3)-5(x-2)]=0
[7x-4][16-3x]=0
7x-4=0 x1=4/7
16-3x=0 x2=16/3 .,
2,
(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x1=0
x2=(1-√2)/(1+√2)

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4(x+3)²=25(x-2)²
4(x+3)²-25(x-2)²=0
[2(x+3)]²-[5(x-2)]²=0
[2(x+3)+5(x-2)][2(x+3)-5(x-2)]=0
[2x+6+5x-10][2x+6-5x+10]=0
[7x-4][16-3x]=0
x1=4/7
x...

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4(x+3)²=25(x-2)²
4(x+3)²-25(x-2)²=0
[2(x+3)]²-[5(x-2)]²=0
[2(x+3)+5(x-2)][2(x+3)-5(x-2)]=0
[2x+6+5x-10][2x+6-5x+10]=0
[7x-4][16-3x]=0
x1=4/7
x2=16/3
(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x1=0
x2=(1-√2)/(1+√2)=[(1-√2)(√2-1)]/[(√2+1)(√2-1)]=2√2-3

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