设函数f(x)=cos(2x-π/3)-cos2x-1怎么化简?

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设函数f(x)=cos(2x-π/3)-cos2x-1怎么化简?

设函数f(x)=cos(2x-π/3)-cos2x-1怎么化简?
设函数f(x)=cos(2x-π/3)-cos2x-1
怎么化简?

设函数f(x)=cos(2x-π/3)-cos2x-1怎么化简?
f(x)=cos(2x-π/3)-cos2x-1
=cos2x*cos(π/3)+ sin2x*sin(π/3) - 2cos2x*cos(π/3)-1
= - [cos2x*cos(π/3)- sin2x*sin(π/3)] -1
=-cos(2x+π/3)-1