作业帮1/Cos²θ=b²/(Cos²θ＋a²－1）怎么化简得Cosθ＝√[（a²－1）／（b²－1）]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 20:53:35
![1/Cos²θ=b²/(Cos²θ＋a²－1）怎么化简得Cosθ＝√[（a²－1）／（b²－1）]](/uploads/image/z/637711-7-1.jpg?t=1%2FCos%26%23178%3B%CE%B8%3Db%26%23178%3B%2F%28Cos%26%23178%3B%CE%B8%EF%BC%8Ba%26%23178%3B%EF%BC%8D1%EF%BC%89%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E5%BE%97Cos%CE%B8%EF%BC%9D%E2%88%9A%5B%EF%BC%88a%26%23178%3B%EF%BC%8D1%EF%BC%89%EF%BC%8F%EF%BC%88b%26%23178%3B%EF%BC%8D1%EF%BC%89%5D)
1/Cos²θ=b²/(Cos²θ＋a²－1）怎么化简得Cosθ＝√[（a²－1）／（b²－1）]
1/Cos²θ=b²/(Cos²θ＋a²－1）怎么化简得Cosθ＝√[（a²－1）／（b²－1）]
1/Cos²θ=b²/(Cos²θ＋a²－1）怎么化简得Cosθ＝√[（a²－1）／（b²－1）]
1/Cos²θ=b²/(Cos²θ＋a²－1）
b²Cos²θ=Cos²θ＋a²－1
(b²-1)Cos²θ=a²－1
Cos²θ=(a²－1)/(b²-1)
Cosθ＝±√[（a²－1）／（b²－1）]