sum((t(i,:)-r(j,:)).^2) matlab程序

sum((t(i,:)-r(j,:)).^2) matlab程序 这样的lingo程序问题出在哪?sets:time/1..88/:income,A,B,rr;fixed/1..6/:g;link(time,fixed):x,y,r,rrr,t;······@for(time(i):@if(t(i,j) #gt# 0,@sum(fixed(j):y(t(i,j),j)*(1+g(j)*r(t(i,j),j)))=x(i,j);,x(i,j)=0));······data部分就省 求大神改一下lingo程序model:sets:time/1..51/:t;rongliang/1..51/:r;link(time,rongliang):x;endsetsmin=@sum(time:t);@for(link:@bin(x));@for(link:@sum(link:x(i,j)*r) lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@for(r(i): @sum(e(j):x(i,j))=a(i));@for(e(j): @sum(r(i):x(i,j))=b(j));end错误如截图: lingo求矩阵中所有元素的和for循环嵌套sets:l/1..209/;r/1..209/;links(l,r):a,x;endsetsdata:enddatamin=@sum(l(i):@sum(r(j):a(i,j)*x(i,j)));@for(links:@bin(x));@for(l(i):@sum(r(j):x(i,j) 用MATLAB运行代码后总显示 Error using Untitled (line 2) Not enough input arguments.下面是我的源程序function dist = dtw(t,r)n = size(t,1);m = size(r,1);% 帧匹配距离矩阵d = zeros(n,m);for i = 1:nfor j = 1:md(i,j) = sum((t(i,:)-r( lingo 括号不匹配min=@sum(machine(i):@sum(section(j):v(i,j)*t(i,j)*fp(i));cv(i,j)用了for，说我模型定义不正确……麻烦你帮我看一下吧， 用lingo做一个非线性规划,Min=@sum(Time(i,j):t(i,j)*@sum(order(k):a(i,k)*a(j,k+1)));这个语法怎么改?a（i,j）是0-1变量 lingo model:sets:number1..3:x;modes1..4:a,b;mode(number,modes):r;endsetsdata:a=50,10,20,15;b=4,5,6,8;enddatamin=@sum(number:x);@for(modes(i):@sum(number(j):x(j)*r(j,i))>=a(i));@for(number(i):@sum(modes(j):b(j)*r(i,j))>=16;@for(number(i):@sum(modes(j) sets:shiduan/1..5/:h,t; xinghao/1..3/:NN,m,MM,G,F,Q; link(xinghao,shiduan):n,w; endsets min=@sum(xinghao(i):(G(i)*t(1)+Q(i))*n(i,1)+(w(i,1)-m(i))*n(i,1)*F(i)*t(1))+ @sum(shiduan(j)|j #ge# 2:G(i)*n(i,j)*t(j)+(w(i,j)-m(i))*n(i,j)*F(j)*t(i)+@if(n(i,j)#g labview公式节点程序编写function dist = dtw(t,r)n = size(t,1);m = size(r,1);% 帧匹配距离矩阵d = zeros(n,m);for i = 1:nfor j = 1:md(i,j) = sum((t(i,:)-r(j,:)).^2);endend% 累积距离矩阵D = ones(n,m) *realmax;D(1,1) = d(1,1);% 动态 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l J e t 'a i m e,J e t ' a d o r e 请高手帮我找下这个Lingo程序的错误!下面是Lingo程序model:sets:hotel/1..10/;format/1..3/;link(hotel,format):x,y,c;endsetsmin=@sum(link:x*y*c);@for(format(j):@sum(hotel(i):(y(i)*r(i,j)))=num(j)/2);@for(format(j):@sum(hotel(i):(y(i)*r1( lingo模型定义不正确 求帮忙!MIN = @SUM( LINKS(I, J): COST(I, J) * VOLUME(I, J))+@SUM(AGENCY(I)|DEMAND(I)#GT#(CAPACITY(I)-@SUM(AGENCY(J):VOLUME(I,J))+@SUM(AGENCY(J):VOLUME(J,I))):DEMAND(I)-(CAPACITY(I)-@SUM(AGENCY(J):VOLUME(I,J))+@SUM(AGENCY c语言求PI值,使其精度小于0.005,为什么运行不到结果啊,#include #include double fun ( double eps){int i=1,s=1,t=1;double j,sum=1.0;while(j>=eps){t=t*i;s=s*(2*i+1);j=1.0*t/s;sum=sum+j;i++;}return sum*2;}main( ){ double x;void NONO ();p 麻烦各位大神帮助为什么A没有被定义?E=0.001;Max=2;F=[0.5 0.7 0.2;0.3 0.5 0.6;0.8 0.4 0.5];N=size(F);r=sum(F');for i=1:N(1)for j=1:N(2)R(i,j)=(r(i)-r(j))/(2*N(1))+0.5;endendE=R./R';W=sum('R)./sum(sum(R));>> for i=1:N(1)S(i)=R(i,1);for j= DTW算法程序最终输出的D（n,m）是一个距离还是一个矩阵?DTW的一般算法实现DTW算法的函数Dtw.mfunction dist = dtw(t,r)n = size(t,1);m = size(r,1);% 帧匹配距离矩阵d = zeros(n,m);for i = 1:nfor j = 1:md(i,j) = sum((t(i