-1,2,63,244,255（A )A.126 B.182 C.268 D.296195/120,182/112,169/104,156/96,( D ),39/24A.142/88 B.96/66 C.76/48 D.52/321,0,8,19,45,( A )A.80 B.62 C.54 D.14,13,17,25,31,38,41,( B )A.43 B.47 C.49 D.53

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-1,2,63,244,255（A )A.126 B.182 C.268 D.296195/120,182/112,169/104,156/96,( D ),39/24A.142/88 B.96/66 C.76/48 D.52/321,0,8,19,45,( A )A.80 B.62 C.54 D.14,13,17,25,31,38,41,( B )A.43 B.47 C.49 D.53
-1,2,63,244,255（A )
A.126 B.182 C.268 D.296
195/120,182/112,169/104,156/96,( D ),39/24
A.142/88 B.96/66 C.76/48 D.52/32
1,0,8,19,45,( A )
A.80 B.62 C.54 D.1
4,13,17,25,31,38,41,( B )
A.43 B.47 C.49 D.53

-1,2,63,244,255（A )A.126 B.182 C.268 D.296195/120,182/112,169/104,156/96,( D ),39/24A.142/88 B.96/66 C.76/48 D.52/321,0,8,19,45,( A )A.80 B.62 C.54 D.14,13,17,25,31,38,41,( B )A.43 B.47 C.49 D.53
1,2,63,244,255,（）
A 9 B28 C126 D 37
-1=0的8次-1
2=1的7次+1
63=2的6次-1
244=3的5次+1
………………答案为126
2.分母都差都为8,分子的差都为13,所以答案为(39+13)/(24+8)=52/32.选D
3两两相加得一个新的数列 1+0=1 0+8=8 8+19=27 19+45=64
分别为1^3 2^3 3^3 4^3 (5^3) 125-45=80
4还是两两一组 13-4=9 25-17=8 38-31=7 -41=6 =47

(a 1)(a 2)(a 3)(a (a+2)(a+1)-a(a-3) a-1/a+2 1-a/-2-a -2×a×1/a 计算：[a-(1/a)]/a^2-2a+1/a a(a-1)(a-2)(a-3)(a-4)因式分解【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ] (通分） a/a^a^a+3a+2 ,a/a^a+2a+1 ,-1/3a+6 （a-a/a+1)/(a*a-2a)*(a+1)/(a*a+3a+2)要详细的计算说明！计算[(a-1)/a*a-4*a+4]-[(a+2)/(a*a-2*a*a)]-4/a a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=? 幂的计算题1、a×a^2×a^3×a^4×a^52、a+2a+3a+4a+a×a^2×a^3×a^4 [a/(a-1)+a/(a+2)](a+2)/(2a平方+3a+1)化简 1+a+a(1+a)+a(1+a)^2+...+a(1+a)^n a/a^2-4 a-1/a-2 a+2/a^2-4a+4 [(a/a-2)-(a/a+2)]÷4a/2-a,其中a=-1/2 (1-16a×a×a×a)÷（4a×a+1)÷(2a+1)²