log【2】(log【8】m) =log【8】(log【2】m),求(log【2】m)的平方 【】内为底

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log【2】(log【8】m) =log【8】(log【2】m),求(log【2】m)的平方 【】内为底

log【2】(log【8】m) =log【8】(log【2】m),求(log【2】m)的平方 【】内为底
log【2】(log【8】m) =log【8】(log【2】m),求(log【2】m)的平方 【】内为底

log【2】(log【8】m) =log【8】(log【2】m),求(log【2】m)的平方 【】内为底
8=2^3,所以log【8】m=三分之一log【2】m
设log【2】m=x
所以log【2】(三分之一x)=三分之一log【2】x,所以三分之一x=x^3,因为x>0,
所以三分之一=x^2,所以(log【2】m)的平方=1/3

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已知:log2|(log8|m)=log8|(log2|m),求(log2|m)².
解:log2|(log2³|m)=log2³|(log2|m)
log2|((1/3)×log2|m)=log2|(log2|m)^(1/3)
(1/3)×log2|m=(log2|m)^(1/3)
则log2|m=3^(3/2)
则(log2...

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已知:log2|(log8|m)=log8|(log2|m),求(log2|m)².
解:log2|(log2³|m)=log2³|(log2|m)
log2|((1/3)×log2|m)=log2|(log2|m)^(1/3)
(1/3)×log2|m=(log2|m)^(1/3)
则log2|m=3^(3/2)
则(log2|m)²=(3^(3/2))²=3³=27

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log【2】(log【2】m^1/3) =log【2】(log【2】m)^1/3
log【2】m^1/3=(log【2】m)^1/3
1/3*log【2】m=(log【2】m)^1/3
1/3*(log【2】m)^2/3=1
(log【2】m)^2=3^3=27
(log【2】m)的平方=27

8^[log【2】(log【8】m)]=8^[log【8】(log【2】m)]
(log【8】m)^3=log【2】m
8^(log【8】m)^3=8^[log【2】m]
8^[log【8】m*[log【8】m]^2]]=2^[3*log【2】m]
m^[log【8】m]^2]=m^3
[log【8】m]^2=3
又log【8】m=1/3log【2】...

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8^[log【2】(log【8】m)]=8^[log【8】(log【2】m)]
(log【8】m)^3=log【2】m
8^(log【8】m)^3=8^[log【2】m]
8^[log【8】m*[log【8】m]^2]]=2^[3*log【2】m]
m^[log【8】m]^2]=m^3
[log【8】m]^2=3
又log【8】m=1/3log【2】m
[log【8】m]^2=1/9[log【2】m]^2=3
[log【2】m]^2=27
我的答案应该没问题,有疑惑请追问

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