数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!

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数学题 关于limit和Continuity的 急求!The function  is given by the formulawhen  X<1 and by the formulawhen 1小于等于x.What value must be chosen for  in order to make this function continuous at 1 ?求a!急求 谢谢!

数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
数学题 关于limit和Continuity的 急求!

The function  is given by the formula

when  X<1 and by the formula

when 1小于等于x.

What value must be chosen for  in order to make this function continuous at 1 ?


求a!


急求 谢谢!

数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
第二个函数式x大于等于1时的形式吧.
求第一个函数在x趋于1(负)时的极限,利用洛贝塔法则,分子就是15x^2-8x+6,这个极限就是等于13.
再求第二个函数在x=1处的函数值,等于9+a,那么
9+a=13
a=4