已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)

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已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)

已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)
已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)

已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)
设g(x)=ax^5+bx^3-cx,即g(x)=f(x)+6
g(-2)=14
g(2)= - g(-2)=-14
f(2)=-14-6=-20


f(-2)=-2^5a-2^3b+2c-6=8

2^5a+2^3b-2c=-14

f(2)=2^5a+2^3b-2c-6
=-14-6
=-20


f(-2)=a(-2)^5+b(-2)^3-c(-2)-6
=-32a-8b+2c-6=8
14=-32a-8b+2c
32a+8b-2c=-14

f(2)=a2^5+b2^3-c*2-6
=32a+8b-2c-6
=-14-6
=-20

f(-2)+6=14
f(2)=-14-6=-20