cos^2 5π/12-sin^2 7π/12=? 求详细过程

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cos^2 5π/12-sin^2 7π/12=? 求详细过程

cos^2 5π/12-sin^2 7π/12=? 求详细过程
cos^2 5π/12-sin^2 7π/12=? 求详细过程

cos^2 5π/12-sin^2 7π/12=? 求详细过程
con²(5π/12)-sin²(7π/12)=cos²(5π/12)-sin²(π-7π/12)=cos²(5π/12)-sin²(5π/12)=cos(2*5π/12)=cos(5π/6)=-(√3)/2

(1)sin(-5π/12) (2)cos(-61π/12) 化简sin(2π+a)cos(π-a)cos(π/2-a)cos(7π/2-a)/cos(π-a)sin(3π-a)sin(-π+a)sin(5π/2+π) 怎么化简sin(2π+a)cos(π-a)cos(π/2-a)cos(7π/2-a)/cos(π-a)sin(3π-a)sin(-π+a)sin(5π/2+π) 已知cos(π/2+a)=2sin(a-π/2),求sin(π-a)+cos(a+π)/求sin(π-a)+cos(a+π)/5cos(5π/2-a)+3sin(7π/2-a) 已知sinθsinβ=-4/7,则cosθcosβ∈已知tan(π-θ)=3,求下式的值 (5xin^3θ+cosθ)/(2cos^3θ+sin^2θcosθ) 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ sin(a-π)+5cos(2π-a)+4cos(π+a)/cos(π-a)-sin(-a) 求 [sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小 sin(α-β)sin(β-r)-cos(α-β)cos(r-β) 1.sin(α-β)sin(β-r)-cos(α-β)cos(r-β)2.( tan4分之5π+tan12分之5π)/(1-tan12分之5π)3.[ sin(α+β)-2sinαcosβ]/2sinαsinβ+cos(α+β) cos^2 5π/12-sin^2 7π/12=? 求详细过程 化简:[sin( π -a) cos( π+a)cos(3/2 π+a )]/cos(3 π-a )sin(3 π+a )sin(5/2 π-a ) 已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α) 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)] 已知sin(a-π)=2cos(2π-a),求(sin(π-a)+5cos(2π-a))/(3cos(π-a)-sin(-a))的值. sin(a-π)=2cos(2π-a).求3cos(π-a)-sin(-a)/sin(π-a)+5cos(2π-a) 若sin(π-a)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)-sin(-a)的值