用matlab解含参数方程组syms x1 x2>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')matlab一直在运行啊 算不出

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用matlab解含参数方程组syms x1 x2>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')matlab一直在运行啊 算不出

用matlab解含参数方程组syms x1 x2>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')matlab一直在运行啊 算不出
用matlab解含参数方程组
syms x1 x2
>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')
matlab一直在运行啊 算不出来
最后 运行出来的答案有1000多页 太恐怖了

用matlab解含参数方程组syms x1 x2>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')matlab一直在运行啊 算不出
建议放弃,solve一般解不了包含形式sin(x)*cos(y)的符号函数.

用matlab解含参数方程组syms x1 x2>> [x1,x2]=solve('s1^2=(x+r*sin(x1)*sin(x2))^2+(r*sin(x1)*cos(x2)+d/2)^2+(h-r*cos(x1))^2','s2^2=(x+r*sin(x1)*sin(x2)-l)^2+(r*sin(x1)*cos(x2)-d/2)^2+(h-r*cos(x1))^2','x1','x2')matlab一直在运行啊 算不出 matlab解带符号的一元六次方程组matlab如何解带符号的一元六次方程组就是定义了syms x real 用matlab解含参变量的方程组x,y是需要输入的变量,运行syms x,y,A,C;x=3;y=3;[A,C]=solve('x*sin(A*pi/180)=y*sin(C*pi/180)','A+C=90')报错是y =3A =[ empty sym ]Warning:Explicit solution could not be found.> In solve at 98In jisuann at matlab 解析解转换数值解用matlab解方程组,用syms x y z 之后solve但是得到的都是解析解,如何能直接得到数值解?要自己编我还用matlab干啥.我意思是matlab有没有直接提供数值解的语句 MATLAB求解参数方程得到含变量的解后怎么代入参数值,syms x y x1 y1 x2 y2 x3 y3 radius;[x,y,radius]=solve('(x-x1)^2+(y-y1)^2=radius^2','(x-x2)^2+(y-y2)^2=radius^2','(x-x3)^2+(y-y3)^2=radius^2')现在已知了x1y1 x2 y2 x3 y3的值, matlab实数矩阵赋值给参数值比如syms x;a=zeros(2,2);b=[1 1+x;x x^2];当我执行a(1,:)=b(1,:);会提示 Conversion to double from sym is not possible.我想大概是含参数的矩阵不能随便赋值给实数矩阵吧.请问一下该怎 求个非线性方程组,六个参数,急.用MATLAB 求不出来哈,代码如下>> syms qn dn dr pn pr cn cr sn sr hn hr t e a o A T u1 k>> syms Fn Fr fn fr>> syms zn zr>>o=0.8;>>a=0.1;>>cn=0.4;>>cr=0.2;>>k=2;>>T=1;>>hn=0.1;>>sn=0.1;>>hr=0.05;>>sr=0. matlab 求参数方程组例如a*x^3-b*y^2exp(a*x^2)-y-1=0解的的x,y用a,b表示这类方程组怎么解,应该用什么函数 请问用matlab怎么解这个定积分方程组只有两个未知数T和π0, β=15 A=0.2 c+v=5 r=0.07.下面是我写的代码,提示没有解.matlab新手,还请懂的人麻烦写一下具体的代码,谢谢! syms T x>> [T,x]=solve('0.2=1 如何求这个二元三次方程组精确解?用matlab他说没有显式解.方程:-100/x^2/y+17/40/x^3/y^2+7505627081381631/9007199254740992/x^2=0,-100/x/y^2+17/40/x^2/y^3=0我输入 clear;>> syms x y;>> [x,y]=solve('-100/x^2/y+17/40/x^3/y^2+7505 可以用matlab解含参数的微分方程吗?我正在进行数学建模, matlab中怎么对f=@(x)(x*x)求导呀?不想用syms matlab绘制多条曲线我在前文用syms定义的参数变量,经过一系列运算求得f=1/x^2p1=1/x^3p2=1/x^4怎样将这些函数都绘制在同一图中?如果写成plot(x,f)会出错,因为我x是syms型的,请问如何解决Error using ==> matlab中不是不用定义变量吗?但为啥有在求方程组解时,需要>> syms x y >> [x,y]=solve(x^2+y-6,y^2+x-6),而不是直接用>> [x,y]=solve(x^2+y-6,y^2+x-6),就行了, 用matlab解带系数的二元三次方程组有两个方程:syms m,v,x,y;[x,y]=solve('(1.5607*10^(-5)*v+x+y)*(1.2125*10^(-3)*v+x)*(3.9059*10^(-4)*v+x+y)=8.5717*10^(-11)*m^2*v^2*(4.3115*10^(-2)*v-x)','(1.5607*10^(-5)*v+x+y)*(7.3826*10^(-7)*v+y)=2.9 matlab中用solve函数求方程解,结果是个表达式,然后我带入参数的值,用subs求的结果怎么有很多个?syms f x T;A=solve('(f/log(0.2))*(0.9)^x=num2str(T)','x');f=960;T=0.001;subs(A) matlab求解带参数的方程组方程如下:x^2+y^2=R^2;(x-4.5)^2+(y+10)^2=R^2其中R为参数,如何求X,Y呢?下面是我的程序:syms x y R;[x y]=solve('x^2+y^2=R^2','(x-4.5)^2+(y+10)^2=R^2','x','y');但是结果却是ans=1.请教各位 100分,谁会用Mathematica解这个参数方程组啊!写出代码也行,能解决的话再加一百.syms a b c x1 y1 z1 x y z;eq1=sym('cosb*cosc*x+sina*sinb*cosc*y-cosa*sinc*y+cosa*sinb*cosc*z+sina*sinc*z=x1') eq2=sym('cosb*sinc*x+sina*