证明根号下【1-cos(-200°)/1-sin(-250°)】+根号下【1-sin430°/1+cos340°】=2/sin20°

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 00:17:35
证明根号下【1-cos(-200°)/1-sin(-250°)】+根号下【1-sin430°/1+cos340°】=2/sin20°

证明根号下【1-cos(-200°)/1-sin(-250°)】+根号下【1-sin430°/1+cos340°】=2/sin20°
证明根号下【1-cos(-200°)/1-sin(-250°)】+根号下【1-sin430°/1+cos340°】=2/sin20°

证明根号下【1-cos(-200°)/1-sin(-250°)】+根号下【1-sin430°/1+cos340°】=2/sin20°
√[1-cos(-200°)/1-sin(-250°)]+√[1-sin430°/1+cos340°]
=√[﹙1+cos20°)/﹙1-cos20°)]+√[﹙1-cos20°)/﹙1+cos20°)]
=﹙1+cos20°)/sin20°+﹙1-cos20°)/sin20°
=2/sin20°