分式方程大家帮忙做一道分式方程,谢谢了.已知a/(X+2) + b/(X+2) = 4X/(X²-4) 则a= ? b= ?不好意思,写错了,是:已知a/(X+2) + b/(X-2) = 4X/(X²-4) 则a= ? b= ?

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分式方程大家帮忙做一道分式方程,谢谢了.已知a/(X+2) +  b/(X+2) = 4X/(X²-4)    则a= ?       b= ?不好意思,写错了,是:已知a/(X+2) +  b/(X-2) = 4X/(X²-4)    则a= ?       b= ?

分式方程大家帮忙做一道分式方程,谢谢了.已知a/(X+2) + b/(X+2) = 4X/(X²-4) 则a= ? b= ?不好意思,写错了,是:已知a/(X+2) + b/(X-2) = 4X/(X²-4) 则a= ? b= ?
分式方程大家帮忙做一道分式方程,谢谢了.
已知a/(X+2) + b/(X+2) = 4X/(X²-4)
则a= ? b= ?
不好意思,写错了,是:已知a/(X+2) + b/(X-2) = 4X/(X²-4)
则a= ? b= ?

分式方程大家帮忙做一道分式方程,谢谢了.已知a/(X+2) + b/(X+2) = 4X/(X²-4) 则a= ? b= ?不好意思,写错了,是:已知a/(X+2) + b/(X-2) = 4X/(X²-4) 则a= ? b= ?
两边乘以(x+2)
a+b=4x/(x-2)
(x-2)(a+b)=4x
(a+b)x-2(a+b)=4x
(a+b-4)x=2(a+b)
x=2(a+b)/(a+b-4)

这题目没问题?

1.方程两边各乘(X²-4);
2.得到:a(X-2)+b(X+2)=4X;
3.合并同类项:(a+b-4)X+2(b-a-2)=0;
4.要使方程等于0,只可能左边的两项都为0
即:a+b-4=0
b-a-2=0
5.所以解得a=1,b=3。