若分式x(x-2)/x^2+2的值为0,则分式2x/x^2-1除以2x/1-x的值为

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若分式x(x-2)/x^2+2的值为0,则分式2x/x^2-1除以2x/1-x的值为

若分式x(x-2)/x^2+2的值为0,则分式2x/x^2-1除以2x/1-x的值为
若分式x(x-2)/x^2+2的值为0,则分式2x/x^2-1除以2x/1-x的值为

若分式x(x-2)/x^2+2的值为0,则分式2x/x^2-1除以2x/1-x的值为
分式2x/x^2-1除以2x/1-x
分式有意义,所以必须满足 x≠0
分式x(x-2)/x^2+2的值为0
x(x-2)=0
x=0(设)或x=2
所以 2x/x^2-1除以2x/1-x=(4/3)除以(-4)=-1/3

2(x-3)/(x +3)=0 2(x-3)=0 x=3 2x/(x -1)÷2x/(1-x) =2x/(x -1)*(1-x)/(2x) =-1/(x+1) =-1/(3+1) =-1/4 望

x(x-2)/x^2+2 = 0
(x^2-2x)/x^2+2 = 0
(x^2-2x+2x^2)/x^2 = 0
(3x^2-2x)/x^2 = 0
(3x-2)/x=0
x=2/3
2x/(x^2-1) ÷ 2x/(1-x) = 2x/(x^2-1) × [-(x-1)/2x] = -1/(x-1) = -1/(2/3-1) = 3